Base | Representation |
---|---|
bin | 1010000110111000011101… |
… | …1111011001111100100100 |
3 | 1110100102111201100201201020 |
4 | 2201232013133121330210 |
5 | 2424040122002123102 |
6 | 35345223143331140 |
7 | 2224625155365312 |
oct | 241560737317444 |
9 | 43312451321636 |
10 | 11113353551652 |
11 | 35a51683a0010 |
12 | 12b5a13750ab0 |
13 | 627ca5633141 |
14 | 2a5c63cb50b2 |
15 | 14413cdd1bbc |
hex | a1b877d9f24 |
11113353551652 has 96 divisors (see below), whose sum is σ = 29266310344320. Its totient is φ = 3251299537920.
The previous prime is 11113353551593. The next prime is 11113353551719. The reversal of 11113353551652 is 25615535331111.
It is a super-3 number, since 3×111133535516523 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 51482248 + ... + 51697664.
It is an arithmetic number, because the mean of its divisors is an integer number (304857399420).
Almost surely, 211113353551652 is an apocalyptic number.
11113353551652 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11113353551652 is an abundant number, since it is smaller than the sum of its proper divisors (18152956792668).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11113353551652 is a wasteful number, since it uses less digits than its factorization.
11113353551652 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 228941 (or 228939 counting only the distinct ones).
The product of its digits is 202500, while the sum is 42.
Adding to 11113353551652 its reverse (25615535331111), we get a palindrome (36728888882763).
The spelling of 11113353551652 in words is "eleven trillion, one hundred thirteen billion, three hundred fifty-three million, five hundred fifty-one thousand, six hundred fifty-two".
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