Base | Representation |
---|---|
bin | 1010000110111000101100… |
… | …0100001110101110010001 |
3 | 1110100102122220020021200002 |
4 | 2201232023010032232101 |
5 | 2424040232331133112 |
6 | 35345233125135345 |
7 | 2224626514300565 |
oct | 241561304165621 |
9 | 43312586207602 |
10 | 11113413536657 |
11 | 35a51992406a3 |
12 | 12b5a2b85a555 |
13 | 627cb4ba6323 |
14 | 2a5c6bc4b6a5 |
15 | 1441432d01c2 |
hex | a1b8b10eb91 |
11113413536657 has 2 divisors, whose sum is σ = 11113413536658. Its totient is φ = 11113413536656.
The previous prime is 11113413536611. The next prime is 11113413536707. The reversal of 11113413536657 is 75663531431111.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11036906529856 + 76507006801 = 3322184^2 + 276599^2 .
It is a cyclic number.
It is not a de Polignac number, because 11113413536657 - 222 = 11113409342353 is a prime.
It is not a weakly prime, because it can be changed into another prime (11113413536857) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556706768328 + 5556706768329.
It is an arithmetic number, because the mean of its divisors is an integer number (5556706768329).
Almost surely, 211113413536657 is an apocalyptic number.
It is an amenable number.
11113413536657 is a deficient number, since it is larger than the sum of its proper divisors (1).
11113413536657 is an equidigital number, since it uses as much as digits as its factorization.
11113413536657 is an evil number, because the sum of its binary digits is even.
The product of its digits is 680400, while the sum is 47.
Adding to 11113413536657 its reverse (75663531431111), we get a palindrome (86776944967768).
The spelling of 11113413536657 in words is "eleven trillion, one hundred thirteen billion, four hundred thirteen million, five hundred thirty-six thousand, six hundred fifty-seven".
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