1111343401300 has 72 divisors (see below), whose sum is σ = 2638660489920. Its totient is φ = 402925555200.

The previous prime is 1111343401283. The next prime is 1111343401307. The reversal of 1111343401300 is 31043431111.

It is a super-2 number, since 2×1111343401300² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1111343401307) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1128280 + ... + 1869679.

It is an arithmetic number, because the mean of its divisors is an integer number (36648062360).

Almost surely, 2^{1111343401300} is an apocalyptic number.

1111343401300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1111343401300 is an abundant number, since it is smaller than the sum of its proper divisors (1527317088620).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1111343401300 is a wasteful number, since it uses less digits than its factorization.

1111343401300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2998321 (or 2998314 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1111343401300 its reverse (31043431111), we get a palindrome (1142386832411).

The spelling of 1111343401300 in words is "one trillion, one hundred eleven billion, three hundred forty-three million, four hundred one thousand, three hundred".