111140300081 has 2 divisors, whose sum is σ = 111140300082. Its totient is φ = 111140300080.

The previous prime is 111140299957. The next prime is 111140300119. The reversal of 111140300081 is 180003041111.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 57304699456 + 53835600625 = 239384^2 + 232025^2 .

It is a cyclic number.

It is not a de Polignac number, because 111140300081 - 2³⁰ = 110066558257 is a prime.

It is a super-3 number, since 3×111140300081³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (111140360081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55570150040 + 55570150041.

It is an arithmetic number, because the mean of its divisors is an integer number (55570150041).

Almost surely, 2^111140300081 is an apocalyptic number.

It is an amenable number.

111140300081 is a deficient number, since it is larger than the sum of its proper divisors (1).

111140300081 is an equidigital number, since it uses as much as digits as its factorization.

111140300081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 20.

Adding to 111140300081 its reverse (180003041111), we get a palindrome (291143341192).

The spelling of 111140300081 in words is "one hundred eleven billion, one hundred forty million, three hundred thousand, eighty-one".