Base | Representation |
---|---|
bin | 10100101100111001… |
… | …11110100100010100 |
3 | 1001200120011110020221 |
4 | 22112130332210110 |
5 | 140230203111200 |
6 | 5034502004124 |
7 | 542263255453 |
oct | 122634764424 |
9 | 31616143227 |
10 | 11114113300 |
11 | 4793699904 |
12 | 21a2116644 |
13 | 1081770004 |
14 | 7760d6b9a |
15 | 450ad091a |
hex | 29673e914 |
11114113300 has 36 divisors (see below), whose sum is σ = 24122206080. Its totient is φ = 4444801120.
The previous prime is 11114113277. The next prime is 11114113331. The reversal of 11114113300 is 331141111.
11114113300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1002387 + ... + 1013413.
It is an arithmetic number, because the mean of its divisors is an integer number (670061280).
Almost surely, 211114113300 is an apocalyptic number.
11114113300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11114113300 is an abundant number, since it is smaller than the sum of its proper divisors (13008092780).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11114113300 is a wasteful number, since it uses less digits than its factorization.
11114113300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21120 (or 21113 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 11114113300 its reverse (331141111), we get a palindrome (11445254411).
The spelling of 11114113300 in words is "eleven billion, one hundred fourteen million, one hundred thirteen thousand, three hundred".
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