11114324231 has 2 divisors, whose sum is σ = 11114324232. Its totient is φ = 11114324230.

The previous prime is 11114324219. The next prime is 11114324233. The reversal of 11114324231 is 13242341111.

It is a strong prime.

It is an emirp because it is prime and its reverse (13242341111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11114324231 - 2¹⁴ = 11114307847 is a prime.

It is a super-2 number, since 2×11114324231² (a number of 21 digits) contains 22 as substring.

Together with 11114324233, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11114324197 and 11114324206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11114324233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5557162115 + 5557162116.

It is an arithmetic number, because the mean of its divisors is an integer number (5557162116).

Almost surely, 2^11114324231 is an apocalyptic number.

11114324231 is a deficient number, since it is larger than the sum of its proper divisors (1).

11114324231 is an equidigital number, since it uses as much as digits as its factorization.

11114324231 is an evil number, because the sum of its binary digits is even.

The product of its digits is 576, while the sum is 23.

Adding to 11114324231 its reverse (13242341111), we get a palindrome (24356665342).

The spelling of 11114324231 in words is "eleven billion, one hundred fourteen million, three hundred twenty-four thousand, two hundred thirty-one".