Base | Representation |
---|---|
bin | 10100101101000011… |
… | …01001001101011011 |
3 | 1001200122110121020002 |
4 | 22112201221031123 |
5 | 140231011232124 |
6 | 5034544123215 |
7 | 542306541656 |
oct | 122641511533 |
9 | 31618417202 |
10 | 11115336539 |
11 | 479435494a |
12 | 21a260650b |
13 | 1081aaaa18 |
14 | 77633489d |
15 | 450c730ae |
hex | 29686935b |
11115336539 has 2 divisors, whose sum is σ = 11115336540. Its totient is φ = 11115336538.
The previous prime is 11115336527. The next prime is 11115336541. The reversal of 11115336539 is 93563351111.
11115336539 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (93563351111) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11115336539 is a prime.
Together with 11115336541, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11115336139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5557668269 + 5557668270.
It is an arithmetic number, because the mean of its divisors is an integer number (5557668270).
Almost surely, 211115336539 is an apocalyptic number.
11115336539 is a deficient number, since it is larger than the sum of its proper divisors (1).
11115336539 is an equidigital number, since it uses as much as digits as its factorization.
11115336539 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 36450, while the sum is 38.
The spelling of 11115336539 in words is "eleven billion, one hundred fifteen million, three hundred thirty-six thousand, five hundred thirty-nine".
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