Search a number
-
+
1112002000231 is a prime number
BaseRepresentation
bin10000001011101000011…
…110111111010101100111
310221022021022221112212211
4100023220132333111213
5121204340003001411
62210502514024251
7143224306021603
oct20135036772547
93838238845784
101112002000231
11399663159451
1215b61b278087
1380b27490365
143bb6d486503
151ddd44b9221
hex102e87bf567

1112002000231 has 2 divisors, whose sum is σ = 1112002000232. Its totient is φ = 1112002000230.

The previous prime is 1112002000201. The next prime is 1112002000237. The reversal of 1112002000231 is 1320002002111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1112002000231 - 213 = 1112001992039 is a prime.

It is a super-2 number, since 2×11120020002312 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1112002000237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556001000115 + 556001000116.

It is an arithmetic number, because the mean of its divisors is an integer number (556001000116).

Almost surely, 21112002000231 is an apocalyptic number.

1112002000231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112002000231 is an equidigital number, since it uses as much as digits as its factorization.

1112002000231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 1112002000231 its reverse (1320002002111), we get a palindrome (2432004002342).

The spelling of 1112002000231 in words is "one trillion, one hundred twelve billion, two million, two hundred thirty-one", and thus it is an aban number.