Base | Representation |
---|---|
bin | 1010000111010001101001… |
… | …0101001110011011111000 |
3 | 1110101001221201202121121220 |
4 | 2201310122111032123320 |
5 | 2424142442144213422 |
6 | 35352301534432040 |
7 | 2225254513201200 |
oct | 241643225163370 |
9 | 43331851677556 |
10 | 11120112101112 |
11 | 35a8016420283 |
12 | 12b719b062620 |
13 | 6288118cac31 |
14 | 2a630573d400 |
15 | 1443d6404e5c |
hex | a1d1a54e6f8 |
11120112101112 has 96 divisors (see below), whose sum is σ = 32397162855120. Its totient is φ = 3171470615040.
The previous prime is 11120112101053. The next prime is 11120112101171. The reversal of 11120112101112 is 21110121102111.
11120112101112 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (11120112101053) and next prime (11120112101171).
It is a junction number, because it is equal to n+sod(n) for n = 11120112101091 and 11120112101100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7833189 + ... + 9143252.
Almost surely, 211120112101112 is an apocalyptic number.
11120112101112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11120112101112 is an abundant number, since it is smaller than the sum of its proper divisors (21277050754008).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11120112101112 is a wasteful number, since it uses less digits than its factorization.
11120112101112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16977021 (or 16977010 counting only the distinct ones).
The product of its (nonzero) digits is 8, while the sum is 15.
Adding to 11120112101112 its reverse (21110121102111), we get a palindrome (32230233203223).
Subtracting 11120112101112 from its reverse (21110121102111), we obtain a palindrome (9990009000999).
It can be divided in two parts, 1112011 and 2101112, that added together give a palindrome (3213123).
The spelling of 11120112101112 in words is "eleven trillion, one hundred twenty billion, one hundred twelve million, one hundred one thousand, one hundred twelve".
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