1112012113 has 2 divisors, whose sum is σ = 1112012114. Its totient is φ = 1112012112.

The previous prime is 1112012101. The next prime is 1112012131. The reversal of 1112012113 is 3112102111.

It is a happy number.

Together with next prime (1112012131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 681366609 + 430645504 = 26103^2 + 20752^2 .

It is an emirp because it is prime and its reverse (3112102111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1112012113 - 2⁵ = 1112012081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1112012093 and 1112012102.

It is not a weakly prime, because it can be changed into another prime (1112012813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556006056 + 556006057.

It is an arithmetic number, because the mean of its divisors is an integer number (556006057).

Almost surely, 2^1112012113 is an apocalyptic number.

It is an amenable number.

1112012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112012113 is an equidigital number, since it uses as much as digits as its factorization.

1112012113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

The square root of 1112012113 is about 33346.8456229371. The cubic root of 1112012113 is about 1036.0240552471.

Adding to 1112012113 its reverse (3112102111), we get a palindrome (4224114224).

The spelling of 1112012113 in words is "one billion, one hundred twelve million, twelve thousand, one hundred thirteen".