Base | Representation |
---|---|
bin | 1011100101111110… |
… | …1110100011011111 |
3 | 22000212222011112011 |
4 | 2321133232203133 |
5 | 22333144231421 |
6 | 1232451052051 |
7 | 140056300666 |
oct | 27137564337 |
9 | 8025864464 |
10 | 3112102111 |
11 | 1357778418 |
12 | 72a2a1027 |
13 | 3a79a4651 |
14 | 217467ddd |
15 | 1333394e1 |
hex | b97ee8df |
3112102111 has 2 divisors, whose sum is σ = 3112102112. Its totient is φ = 3112102110.
The previous prime is 3112102099. The next prime is 3112102117. The reversal of 3112102111 is 1112012113.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (1112012113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3112102111 - 27 = 3112101983 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3112102091 and 3112102100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3112102117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556051055 + 1556051056.
It is an arithmetic number, because the mean of its divisors is an integer number (1556051056).
Almost surely, 23112102111 is an apocalyptic number.
3112102111 is a deficient number, since it is larger than the sum of its proper divisors (1).
3112102111 is an equidigital number, since it uses as much as digits as its factorization.
3112102111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 13.
The square root of 3112102111 is about 55786.2179305964. The cubic root of 3112102111 is about 1459.9947005187.
Adding to 3112102111 its reverse (1112012113), we get a palindrome (4224114224).
The spelling of 3112102111 in words is "three billion, one hundred twelve million, one hundred two thousand, one hundred eleven".
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