11120977804373 has 2 divisors, whose sum is σ = 11120977804374. Its totient is φ = 11120977804372.

The previous prime is 11120977804333. The next prime is 11120977804379. The reversal of 11120977804373 is 37340877902111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8688681789649 + 2432296014724 = 2947657^2 + 1559582^2 .

It is a cyclic number.

It is not a de Polignac number, because 11120977804373 - 2³⁰ = 11119904062549 is a prime.

It is a super-2 number, since 2×11120977804373² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11120977804379) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560488902186 + 5560488902187.

It is an arithmetic number, because the mean of its divisors is an integer number (5560488902187).

Almost surely, 2^{11120977804373} is an apocalyptic number.

It is an amenable number.

11120977804373 is a deficient number, since it is larger than the sum of its proper divisors (1).

11120977804373 is an equidigital number, since it uses as much as digits as its factorization.

11120977804373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1778112, while the sum is 53.

The spelling of 11120977804373 in words is "eleven trillion, one hundred twenty billion, nine hundred seventy-seven million, eight hundred four thousand, three hundred seventy-three".