Base | Representation |
---|---|
bin | 1010000111010100111111… |
… | …0110111001010110111011 |
3 | 1110101011021022112201010021 |
4 | 2201311033312321112323 |
5 | 2424201312042320443 |
6 | 35352531014231311 |
7 | 2225315666216341 |
oct | 241651766712673 |
9 | 43334238481107 |
10 | 11121010120123 |
11 | 35a843731a252 |
12 | 12b73ab955537 |
13 | 62892597ca27 |
14 | 2a638cb01991 |
15 | 14443a18e9ed |
hex | a1d4fdb95bb |
11121010120123 has 2 divisors, whose sum is σ = 11121010120124. Its totient is φ = 11121010120122.
The previous prime is 11121010120097. The next prime is 11121010120141. The reversal of 11121010120123 is 32102101012111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11121010120123 - 237 = 10983571166651 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11121010120097 and 11121010120106.
It is not a weakly prime, because it can be changed into another prime (11121010120523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560505060061 + 5560505060062.
It is an arithmetic number, because the mean of its divisors is an integer number (5560505060062).
Almost surely, 211121010120123 is an apocalyptic number.
11121010120123 is a deficient number, since it is larger than the sum of its proper divisors (1).
11121010120123 is an equidigital number, since it uses as much as digits as its factorization.
11121010120123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 11121010120123 its reverse (32102101012111), we get a palindrome (43223111132234).
The spelling of 11121010120123 in words is "eleven trillion, one hundred twenty-one billion, ten million, one hundred twenty thousand, one hundred twenty-three".
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