Base | Representation |
---|---|
bin | 110011110010010100… |
… | …1010100100111101101 |
3 | 101122001102122112010112 |
4 | 1213210221110213231 |
5 | 3310224304020023 |
6 | 123031140545405 |
7 | 11014615162454 |
oct | 1474451244755 |
9 | 348042575115 |
10 | 111210220013 |
11 | 431892a7342 |
12 | 196780b2265 |
13 | a64415c119 |
14 | 554dc13b9b |
15 | 2d5d4a1478 |
hex | 19e4a549ed |
111210220013 has 2 divisors, whose sum is σ = 111210220014. Its totient is φ = 111210220012.
The previous prime is 111210219979. The next prime is 111210220019. The reversal of 111210220013 is 310022012111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 104340628324 + 6869591689 = 323018^2 + 82883^2 .
It is a cyclic number.
It is not a de Polignac number, because 111210220013 - 222 = 111206025709 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 111210220013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111210220019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55605110006 + 55605110007.
It is an arithmetic number, because the mean of its divisors is an integer number (55605110007).
Almost surely, 2111210220013 is an apocalyptic number.
It is an amenable number.
111210220013 is a deficient number, since it is larger than the sum of its proper divisors (1).
111210220013 is an equidigital number, since it uses as much as digits as its factorization.
111210220013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 111210220013 its reverse (310022012111), we get a palindrome (421232232124).
The spelling of 111210220013 in words is "one hundred eleven billion, two hundred ten million, two hundred twenty thousand, thirteen".
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