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111211010202157 is a prime number
BaseRepresentation
bin11001010010010101010100…
…110000100001101000101101
3112120202200001111220010001121
4121102111110300201220231
5104034040122102432112
61032305344403140541
732265505335426415
oct3122252460415055
9476680044803047
10111211010202157
1132487362aa3108
1210581532374751
134a091cb946388
141d668da833645
15ccccc0d05407
hex652554c21a2d

111211010202157 has 2 divisors, whose sum is σ = 111211010202158. Its totient is φ = 111211010202156.

The previous prime is 111211010202049. The next prime is 111211010202221. The reversal of 111211010202157 is 751202010112111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90074316581001 + 21136693621156 = 9490749^2 + 4597466^2 .

It is a cyclic number.

It is not a de Polignac number, because 111211010202157 - 219 = 111211009677869 is a prime.

It is a super-3 number, since 3×1112110102021573 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111211010205157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55605505101078 + 55605505101079.

It is an arithmetic number, because the mean of its divisors is an integer number (55605505101079).

Almost surely, 2111211010202157 is an apocalyptic number.

It is an amenable number.

111211010202157 is a deficient number, since it is larger than the sum of its proper divisors (1).

111211010202157 is an equidigital number, since it uses as much as digits as its factorization.

111211010202157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 280, while the sum is 25.

Adding to 111211010202157 its reverse (751202010112111), we get a palindrome (862413020314268).

The spelling of 111211010202157 in words is "one hundred eleven trillion, two hundred eleven billion, ten million, two hundred two thousand, one hundred fifty-seven".