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111211022002019 is a prime number
BaseRepresentation
bin11001010010010101010101…
…011101100010011101100011
3112120202200002100002121102112
4121102111111131202131203
5104034040133113031034
61032305345504105535
732265505540633352
oct3122252535423543
9476680070077375
10111211022002019
1132487369722565
12105815363052ab
134a09201218244
141d668dc225999
15ccccc1d867ce
hex652555762763

111211022002019 has 2 divisors, whose sum is σ = 111211022002020. Its totient is φ = 111211022002018.

The previous prime is 111211022002001. The next prime is 111211022002021. The reversal of 111211022002019 is 910200220112111.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111211022002019 - 220 = 111211020953443 is a prime.

It is a super-2 number, since 2×1112110220020192 (a number of 29 digits) contains 22 as substring.

Together with 111211022002021, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 111211022001985 and 111211022002003.

It is not a weakly prime, because it can be changed into another prime (111211022002919) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55605511001009 + 55605511001010.

It is an arithmetic number, because the mean of its divisors is an integer number (55605511001010).

Almost surely, 2111211022002019 is an apocalyptic number.

111211022002019 is a deficient number, since it is larger than the sum of its proper divisors (1).

111211022002019 is an equidigital number, since it uses as much as digits as its factorization.

111211022002019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 23.

The spelling of 111211022002019 in words is "one hundred eleven trillion, two hundred eleven billion, twenty-two million, two thousand, nineteen".