Base | Representation |
---|---|
bin | 11001010010010101010101… |
… | …011101100010011101100011 |
3 | 112120202200002100002121102112 |
4 | 121102111111131202131203 |
5 | 104034040133113031034 |
6 | 1032305345504105535 |
7 | 32265505540633352 |
oct | 3122252535423543 |
9 | 476680070077375 |
10 | 111211022002019 |
11 | 32487369722565 |
12 | 105815363052ab |
13 | 4a09201218244 |
14 | 1d668dc225999 |
15 | ccccc1d867ce |
hex | 652555762763 |
111211022002019 has 2 divisors, whose sum is σ = 111211022002020. Its totient is φ = 111211022002018.
The previous prime is 111211022002001. The next prime is 111211022002021. The reversal of 111211022002019 is 910200220112111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111211022002019 - 220 = 111211020953443 is a prime.
It is a super-2 number, since 2×1112110220020192 (a number of 29 digits) contains 22 as substring.
Together with 111211022002021, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 111211022001985 and 111211022002003.
It is not a weakly prime, because it can be changed into another prime (111211022002919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55605511001009 + 55605511001010.
It is an arithmetic number, because the mean of its divisors is an integer number (55605511001010).
Almost surely, 2111211022002019 is an apocalyptic number.
111211022002019 is a deficient number, since it is larger than the sum of its proper divisors (1).
111211022002019 is an equidigital number, since it uses as much as digits as its factorization.
111211022002019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 23.
The spelling of 111211022002019 in words is "one hundred eleven trillion, two hundred eleven billion, twenty-two million, two thousand, nineteen".
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