Base | Representation |
---|---|
bin | 11001010010010110010000… |
… | …011110110110010000111111 |
3 | 112120202202122100022221002201 |
4 | 121102112100132312100333 |
5 | 104034044200110413043 |
6 | 1032310032035332331 |
7 | 32265542223324046 |
oct | 3122262036662077 |
9 | 476682570287081 |
10 | 111212012201023 |
11 | 32487827661748 |
12 | 10581771a510a7 |
13 | 4a0932b403306 |
14 | 1d6699394155d |
15 | cccd2dc7dc4d |
hex | 6525907b643f |
111212012201023 has 2 divisors, whose sum is σ = 111212012201024. Its totient is φ = 111212012201022.
The previous prime is 111212012200979. The next prime is 111212012201077. The reversal of 111212012201023 is 320102210212111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 111212012201023 - 245 = 76027640112191 is a prime.
It is a super-3 number, since 3×1112120122010233 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111212012201723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55606006100511 + 55606006100512.
It is an arithmetic number, because the mean of its divisors is an integer number (55606006100512).
Almost surely, 2111212012201023 is an apocalyptic number.
111212012201023 is a deficient number, since it is larger than the sum of its proper divisors (1).
111212012201023 is an equidigital number, since it uses as much as digits as its factorization.
111212012201023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 111212012201023 its reverse (320102210212111), we get a palindrome (431314222413134).
The spelling of 111212012201023 in words is "one hundred eleven trillion, two hundred twelve billion, twelve million, two hundred one thousand, twenty-three".
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