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11121331343351 is a prime number
BaseRepresentation
bin1010000111010110001100…
…0000010000111111110111
31110101012002200222112112212
42201311203000100333313
52424202441310441401
635353022531204035
72225326646451245
oct241654300207767
943335080875485
1011121331343351
1135a8591679a99
1212b747b44661b
1362897739b948
142a63bd63b795
15144458491dbb
hexa1d63010ff7

11121331343351 has 2 divisors, whose sum is σ = 11121331343352. Its totient is φ = 11121331343350.

The previous prime is 11121331343281. The next prime is 11121331343357. The reversal of 11121331343351 is 15334313312111.

11121331343351 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11121331343351 - 230 = 11120257601527 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11121331343357) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560665671675 + 5560665671676.

It is an arithmetic number, because the mean of its divisors is an integer number (5560665671676).

Almost surely, 211121331343351 is an apocalyptic number.

11121331343351 is a deficient number, since it is larger than the sum of its proper divisors (1).

11121331343351 is an equidigital number, since it uses as much as digits as its factorization.

11121331343351 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9720, while the sum is 32.

Adding to 11121331343351 its reverse (15334313312111), we get a palindrome (26455644655462).

The spelling of 11121331343351 in words is "eleven trillion, one hundred twenty-one billion, three hundred thirty-one million, three hundred forty-three thousand, three hundred fifty-one".