Base | Representation |
---|---|
bin | 1010000111010110110101… |
… | …1100011001000001001111 |
3 | 1110101012112220112211101111 |
4 | 2201311231130121001033 |
5 | 2424203321130112044 |
6 | 35353052145152451 |
7 | 2225334204246226 |
oct | 241655534310117 |
9 | 43335486484344 |
10 | 11121506488399 |
11 | 35a867152606a |
12 | 12b750a02b727 |
13 | 6289a4762a78 |
14 | 2a63d89cdcbd |
15 | 144468a3bb34 |
hex | a1d6d71904f |
11121506488399 has 2 divisors, whose sum is σ = 11121506488400. Its totient is φ = 11121506488398.
The previous prime is 11121506488397. The next prime is 11121506488403. The reversal of 11121506488399 is 99388460512111.
11121506488399 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11121506488399 - 21 = 11121506488397 is a prime.
Together with 11121506488397, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11121506488397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5560753244199 + 5560753244200.
It is an arithmetic number, because the mean of its divisors is an integer number (5560753244200).
Almost surely, 211121506488399 is an apocalyptic number.
11121506488399 is a deficient number, since it is larger than the sum of its proper divisors (1).
11121506488399 is an equidigital number, since it uses as much as digits as its factorization.
11121506488399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3732480, while the sum is 58.
The spelling of 11121506488399 in words is "eleven trillion, one hundred twenty-one billion, five hundred six million, four hundred eighty-eight thousand, three hundred ninety-nine".
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