11122101311 has 2 divisors, whose sum is σ = 11122101312. Its totient is φ = 11122101310.

The previous prime is 11122101293. The next prime is 11122101313. The reversal of 11122101311 is 11310122111.

It is a strong prime.

It is an emirp because it is prime and its reverse (11310122111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11122101311 - 2¹⁰ = 11122100287 is a prime.

It is a super-2 number, since 2×11122101311² (a number of 21 digits) contains 22 as substring.

Together with 11122101313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11122101313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561050655 + 5561050656.

It is an arithmetic number, because the mean of its divisors is an integer number (5561050656).

Almost surely, 2^11122101311 is an apocalyptic number.

11122101311 is a deficient number, since it is larger than the sum of its proper divisors (1).

11122101311 is an equidigital number, since it uses as much as digits as its factorization.

11122101311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 11122101311 its reverse (11310122111), we get a palindrome (22432223422).

The spelling of 11122101311 in words is "eleven billion, one hundred twenty-two million, one hundred one thousand, three hundred eleven".