Base | Representation |
---|---|
bin | 110011110010101011… |
… | …0010011110010100101 |
3 | 101122002020211200012021 |
4 | 1213211112103302211 |
5 | 3310240313404333 |
6 | 123032241423141 |
7 | 11015120340562 |
oct | 1474526236245 |
9 | 348066750167 |
10 | 111222013093 |
11 | 43194a21694 |
12 | 1968003aab1 |
13 | a64672ab89 |
14 | 5551603869 |
15 | 2d5e53082d |
hex | 19e5593ca5 |
111222013093 has 2 divisors, whose sum is σ = 111222013094. Its totient is φ = 111222013092.
The previous prime is 111222013087. The next prime is 111222013109. The reversal of 111222013093 is 390310222111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 70914624804 + 40307388289 = 266298^2 + 200767^2 .
It is a cyclic number.
It is not a de Polignac number, because 111222013093 - 29 = 111222012581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111222013043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55611006546 + 55611006547.
It is an arithmetic number, because the mean of its divisors is an integer number (55611006547).
Almost surely, 2111222013093 is an apocalyptic number.
It is an amenable number.
111222013093 is a deficient number, since it is larger than the sum of its proper divisors (1).
111222013093 is an equidigital number, since it uses as much as digits as its factorization.
111222013093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 111222013093 in words is "one hundred eleven billion, two hundred twenty-two million, thirteen thousand, ninety-three".
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