Base | Representation |
---|---|
bin | 110011110010101011… |
… | …0010101111101111101 |
3 | 101122002020212010102122 |
4 | 1213211112111331331 |
5 | 3310240314201023 |
6 | 123032241532325 |
7 | 11015120405564 |
oct | 1474526257575 |
9 | 348066763378 |
10 | 111222022013 |
11 | 43194a28363 |
12 | 196800440a5 |
13 | a646731c5b |
14 | 5551606bdb |
15 | 2d5e5332c8 |
hex | 19e5595f7d |
111222022013 has 2 divisors, whose sum is σ = 111222022014. Its totient is φ = 111222022012.
The previous prime is 111222021997. The next prime is 111222022061. The reversal of 111222022013 is 310220222111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 99075116644 + 12146905369 = 314762^2 + 110213^2 .
It is a cyclic number.
It is not a de Polignac number, because 111222022013 - 24 = 111222021997 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 111222021982 and 111222022000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111222022313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55611011006 + 55611011007.
It is an arithmetic number, because the mean of its divisors is an integer number (55611011007).
Almost surely, 2111222022013 is an apocalyptic number.
It is an amenable number.
111222022013 is a deficient number, since it is larger than the sum of its proper divisors (1).
111222022013 is an equidigital number, since it uses as much as digits as its factorization.
111222022013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 111222022013 its reverse (310220222111), we get a palindrome (421442244124).
The spelling of 111222022013 in words is "one hundred eleven billion, two hundred twenty-two million, twenty-two thousand, thirteen".
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