11122656133 has 2 divisors, whose sum is σ = 11122656134. Its totient is φ = 11122656132.

The previous prime is 11122656073. The next prime is 11122656157. The reversal of 11122656133 is 33165622111.

11122656133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7834551169 + 3288104964 = 88513^2 + 57342^2 .

It is an emirp because it is prime and its reverse (33165622111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11122656133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11122656095 and 11122656104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11123656133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561328066 + 5561328067.

It is an arithmetic number, because the mean of its divisors is an integer number (5561328067).

Almost surely, 2^11122656133 is an apocalyptic number.

It is an amenable number.

11122656133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11122656133 is an equidigital number, since it uses as much as digits as its factorization.

11122656133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6480, while the sum is 31.

The spelling of 11122656133 in words is "eleven billion, one hundred twenty-two million, six hundred fifty-six thousand, one hundred thirty-three".