1112313044041 has 2 divisors, whose sum is σ = 1112313044042. Its totient is φ = 1112313044040.

The previous prime is 1112313044039. The next prime is 1112313044057. The reversal of 1112313044041 is 1404403132111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1109028034816 + 3285009225 = 1053104^2 + 57315^2 .

It is a cyclic number.

It is not a de Polignac number, because 1112313044041 - 2¹ = 1112313044039 is a prime.

Together with 1112313044039, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1112313043997 and 1112313044015.

It is not a weakly prime, because it can be changed into another prime (1112313084041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556156522020 + 556156522021.

It is an arithmetic number, because the mean of its divisors is an integer number (556156522021).

Almost surely, 2^{1112313044041} is an apocalyptic number.

It is an amenable number.

1112313044041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112313044041 is an equidigital number, since it uses as much as digits as its factorization.

1112313044041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1112313044041 its reverse (1404403132111), we get a palindrome (2516716176152).

The spelling of 1112313044041 in words is "one trillion, one hundred twelve billion, three hundred thirteen million, forty-four thousand, forty-one".