111243304423 has 2 divisors, whose sum is σ = 111243304424. Its totient is φ = 111243304422.

The previous prime is 111243304397. The next prime is 111243304427. The reversal of 111243304423 is 324403342111.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (324403342111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111243304423 - 2⁵ = 111243304391 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111243304391 and 111243304400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111243304427) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55621652211 + 55621652212.

It is an arithmetic number, because the mean of its divisors is an integer number (55621652212).

Almost surely, 2^111243304423 is an apocalyptic number.

111243304423 is a deficient number, since it is larger than the sum of its proper divisors (1).

111243304423 is an equidigital number, since it uses as much as digits as its factorization.

111243304423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 111243304423 its reverse (324403342111), we get a palindrome (435646646534).

The spelling of 111243304423 in words is "one hundred eleven billion, two hundred forty-three million, three hundred four thousand, four hundred twenty-three".