1112721433 has 2 divisors, whose sum is σ = 1112721434. Its totient is φ = 1112721432.

The previous prime is 1112721431. The next prime is 1112721473. The reversal of 1112721433 is 3341272111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1051834624 + 60886809 = 32432^2 + 7803^2 .

It is a cyclic number.

It is not a de Polignac number, because 1112721433 - 2¹ = 1112721431 is a prime.

Together with 1112721431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1112721398 and 1112721407.

It is not a weakly prime, because it can be changed into another prime (1112721431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556360716 + 556360717.

It is an arithmetic number, because the mean of its divisors is an integer number (556360717).

Almost surely, 2^1112721433 is an apocalyptic number.

It is an amenable number.

1112721433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112721433 is an equidigital number, since it uses as much as digits as its factorization.

1112721433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1008, while the sum is 25.

The square root of 1112721433 is about 33357.4794161669. The cubic root of 1112721433 is about 1036.2442915732.

Adding to 1112721433 its reverse (3341272111), we get a palindrome (4453993544).

The spelling of 1112721433 in words is "one billion, one hundred twelve million, seven hundred twenty-one thousand, four hundred thirty-three".