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11130013314331 is a prime number
BaseRepresentation
bin1010000111110110100001…
…1111010110110100011011
31110102000111202122100202121
42201331220133112310123
52424323231402024311
635401020232042111
72226055051133062
oct241755037266433
943360452570677
1011130013314331
1136012373a231a
1212b90a2b33337
1362972bcaab92
142a69a47091d9
151447b579cb71
hexa1f687d6d1b

11130013314331 has 2 divisors, whose sum is σ = 11130013314332. Its totient is φ = 11130013314330.

The previous prime is 11130013314323. The next prime is 11130013314421. The reversal of 11130013314331 is 13341331003111.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11130013314331 - 23 = 11130013314323 is a prime.

It is a super-2 number, since 2×111300133143312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11130013314296 and 11130013314305.

It is not a weakly prime, because it can be changed into another prime (11130013317331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565006657165 + 5565006657166.

It is an arithmetic number, because the mean of its divisors is an integer number (5565006657166).

Almost surely, 211130013314331 is an apocalyptic number.

11130013314331 is a deficient number, since it is larger than the sum of its proper divisors (1).

11130013314331 is an equidigital number, since it uses as much as digits as its factorization.

11130013314331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 11130013314331 its reverse (13341331003111), we get a palindrome (24471344317442).

The spelling of 11130013314331 in words is "eleven trillion, one hundred thirty billion, thirteen million, three hundred fourteen thousand, three hundred thirty-one".