1113002000119 has 2 divisors, whose sum is σ = 1113002000120. Its totient is φ = 1113002000118.

The previous prime is 1113002000017. The next prime is 1113002000183. The reversal of 1113002000119 is 9110002003111.

It is a strong prime.

It is an emirp because it is prime and its reverse (9110002003111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1113002000119 - 2²³ = 1112993611511 is a prime.

It is a super-2 number, since 2×1113002000119² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1113002000096 and 1113002000105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1113002000189) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556501000059 + 556501000060.

It is an arithmetic number, because the mean of its divisors is an integer number (556501000060).

Almost surely, 2^{1113002000119} is an apocalyptic number.

1113002000119 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113002000119 is an equidigital number, since it uses as much as digits as its factorization.

1113002000119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 19.

The spelling of 1113002000119 in words is "one trillion, one hundred thirteen billion, two million, one hundred nineteen", and thus it is an aban number.