Base | Representation |
---|---|
bin | 10000001100100100000… |
… | …101101011111100110111 |
3 | 10221101212000121210221002 |
4 | 100030210011223330313 |
5 | 121213412003001213 |
6 | 2211150035313515 |
7 | 143261140622423 |
oct | 20144405537467 |
9 | 3841760553832 |
10 | 1113002000183 |
11 | 39a026682197 |
12 | 15b85a14b89b |
13 | 80c566ca4c8 |
14 | 3bc261d3b83 |
15 | 1de4219a658 |
hex | 1032416bf37 |
1113002000183 has 2 divisors, whose sum is σ = 1113002000184. Its totient is φ = 1113002000182.
The previous prime is 1113002000119. The next prime is 1113002000189. The reversal of 1113002000183 is 3810002003111.
It is a strong prime.
It is an emirp because it is prime and its reverse (3810002003111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1113002000183 - 26 = 1113002000119 is a prime.
It is a super-2 number, since 2×11130020001832 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113002000189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556501000091 + 556501000092.
It is an arithmetic number, because the mean of its divisors is an integer number (556501000092).
Almost surely, 21113002000183 is an apocalyptic number.
1113002000183 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113002000183 is an equidigital number, since it uses as much as digits as its factorization.
1113002000183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 1113002000183 its reverse (3810002003111), we get a palindrome (4923004003294).
The spelling of 1113002000183 in words is "one trillion, one hundred thirteen billion, two million, one hundred eighty-three", and thus it is an aban number.
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