Base | Representation |
---|---|
bin | 10100101110110011… |
… | …01010100110111101 |
3 | 1001201200002201100101 |
4 | 22113121222212331 |
5 | 140243241203313 |
6 | 5040231001101 |
7 | 542545425463 |
oct | 122731524675 |
9 | 31650081311 |
10 | 11130022333 |
11 | 47a1675571 |
12 | 21a7509191 |
13 | 1084b50341 |
14 | 778278833 |
15 | 4521c45dd |
hex | 29766a9bd |
11130022333 has 2 divisors, whose sum is σ = 11130022334. Its totient is φ = 11130022332.
The previous prime is 11130022327. The next prime is 11130022339. The reversal of 11130022333 is 33322003111.
It is a balanced prime because it is at equal distance from previous prime (11130022327) and next prime (11130022339).
It can be written as a sum of positive squares in only one way, i.e., 6584835609 + 4545186724 = 81147^2 + 67418^2 .
It is a cyclic number.
It is not a de Polignac number, because 11130022333 - 25 = 11130022301 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11130022333.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11130022339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565011166 + 5565011167.
It is an arithmetic number, because the mean of its divisors is an integer number (5565011167).
Almost surely, 211130022333 is an apocalyptic number.
It is an amenable number.
11130022333 is a deficient number, since it is larger than the sum of its proper divisors (1).
11130022333 is an equidigital number, since it uses as much as digits as its factorization.
11130022333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 11130022333 its reverse (33322003111), we get a palindrome (44452025444).
The spelling of 11130022333 in words is "eleven billion, one hundred thirty million, twenty-two thousand, three hundred thirty-three".
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