Base | Representation |
---|---|
bin | 10100101110110011… |
… | …01011000111110111 |
3 | 1001201200002211020101 |
4 | 22113121223013313 |
5 | 140243241240224 |
6 | 5040231014531 |
7 | 542545434562 |
oct | 122731530767 |
9 | 31650084211 |
10 | 11130024439 |
11 | 47a1677106 |
12 | 21a750a447 |
13 | 1084b512a1 |
14 | 7782794d9 |
15 | 4521c5044 |
hex | 29766b1f7 |
11130024439 has 2 divisors, whose sum is σ = 11130024440. Its totient is φ = 11130024438.
The previous prime is 11130024431. The next prime is 11130024467. The reversal of 11130024439 is 93442003111.
It is an a-pointer prime, because the next prime (11130024467) can be obtained adding 11130024439 to its sum of digits (28).
It is a weak prime.
It is an emirp because it is prime and its reverse (93442003111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11130024439 - 23 = 11130024431 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11130024431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565012219 + 5565012220.
It is an arithmetic number, because the mean of its divisors is an integer number (5565012220).
Almost surely, 211130024439 is an apocalyptic number.
11130024439 is a deficient number, since it is larger than the sum of its proper divisors (1).
11130024439 is an equidigital number, since it uses as much as digits as its factorization.
11130024439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 28.
The spelling of 11130024439 in words is "eleven billion, one hundred thirty million, twenty-four thousand, four hundred thirty-nine".
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