111300330113130 has 32 divisors (see below), whose sum is σ = 268519330464768. Its totient is φ = 29524694897600.

The previous prime is 111300330113129. The next prime is 111300330113173. The reversal of 111300330113130 is 31311033003111.

It is a junction number, because it is equal to n+sod(n) for n = 111300330113097 and 111300330113106.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9712064961 + ... + 9712076420.

It is an arithmetic number, because the mean of its divisors is an integer number (8391229077024).

Almost surely, 2^{111300330113130} is an apocalyptic number.

111300330113130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

111300330113130 is an abundant number, since it is smaller than the sum of its proper divisors (157219000351638).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111300330113130 is a wasteful number, since it uses less digits than its factorization.

111300330113130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19424141582.

The product of its (nonzero) digits is 243, while the sum is 21.

Adding to 111300330113130 its reverse (31311033003111), we get a palindrome (142611363116241).

The spelling of 111300330113130 in words is "one hundred eleven trillion, three hundred billion, three hundred thirty million, one hundred thirteen thousand, one hundred thirty".