Base | Representation |
---|---|
bin | 10000001100100100100… |
… | …100100101111100001111 |
3 | 10221101212120212102120112 |
4 | 100030210210211330033 |
5 | 121213421041231111 |
6 | 2211150525110235 |
7 | 143261266525112 |
oct | 20144444457417 |
9 | 3841776772515 |
10 | 1113010102031 |
11 | 39a030206233 |
12 | 15b8609b837b |
13 | 80c582a60b9 |
14 | 3bc27302579 |
15 | 1de42c4ae8b |
hex | 10324925f0f |
1113010102031 has 2 divisors, whose sum is σ = 1113010102032. Its totient is φ = 1113010102030.
The previous prime is 1113010102027. The next prime is 1113010102079. The reversal of 1113010102031 is 1302010103111.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1113010102031 - 22 = 1113010102027 is a prime.
It is a super-2 number, since 2×11130101020312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1113010101997 and 1113010102015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113010102931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556505051015 + 556505051016.
It is an arithmetic number, because the mean of its divisors is an integer number (556505051016).
Almost surely, 21113010102031 is an apocalyptic number.
1113010102031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113010102031 is an equidigital number, since it uses as much as digits as its factorization.
1113010102031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 1113010102031 its reverse (1302010103111), we get a palindrome (2415020205142).
The spelling of 1113010102031 in words is "one trillion, one hundred thirteen billion, ten million, one hundred two thousand, thirty-one".
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