1113033000103 has 2 divisors, whose sum is σ = 1113033000104. Its totient is φ = 1113033000102.

The previous prime is 1113033000083. The next prime is 1113033000119. The reversal of 1113033000103 is 3010003303111.

It is an a-pointer prime, because the next prime (1113033000119) can be obtained adding 1113033000103 to its sum of digits (16).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1113033000103 - 2¹³ = 1113032991911 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1113033000133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556516500051 + 556516500052.

It is an arithmetic number, because the mean of its divisors is an integer number (556516500052).

Almost surely, 2^{1113033000103} is an apocalyptic number.

1113033000103 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113033000103 is an equidigital number, since it uses as much as digits as its factorization.

1113033000103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 1113033000103 its reverse (3010003303111), we get a palindrome (4123036303214).

The spelling of 1113033000103 in words is "one trillion, one hundred thirteen billion, thirty-three million, one hundred three", and thus it is an aban number.