11130402013 has 2 divisors, whose sum is σ = 11130402014. Its totient is φ = 11130402012.

The previous prime is 11130402011. The next prime is 11130402071. The reversal of 11130402013 is 31020403111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8390193604 + 2740208409 = 91598^2 + 52347^2 .

It is an emirp because it is prime and its reverse (31020403111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11130402013 - 2¹ = 11130402011 is a prime.

Together with 11130402011, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11130402011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565201006 + 5565201007.

It is an arithmetic number, because the mean of its divisors is an integer number (5565201007).

Almost surely, 2^11130402013 is an apocalyptic number.

It is an amenable number.

11130402013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11130402013 is an equidigital number, since it uses as much as digits as its factorization.

11130402013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 11130402013 its reverse (31020403111), we get a palindrome (42150805124).

The spelling of 11130402013 in words is "eleven billion, one hundred thirty million, four hundred two thousand, thirteen".