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1113054350047 is a prime number
BaseRepresentation
bin10000001100100111001…
…101011000101011011111
310221101222200010110102221
4100030213031120223133
5121214013403200142
62211155145330211
7143262344605063
oct20144715305337
93841880113387
101113054350047
1139a053188442
1215b873796967
1380c644c9363
143bc2d13daa3
151de46a8b767
hex10327358adf

1113054350047 has 2 divisors, whose sum is σ = 1113054350048. Its totient is φ = 1113054350046.

The previous prime is 1113054350041. The next prime is 1113054350099. The reversal of 1113054350047 is 7400534503111.

It is a weak prime.

It is an emirp because it is prime and its reverse (7400534503111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1113054350047 - 219 = 1113053825759 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1113054349994 and 1113054350021.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1113054350041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556527175023 + 556527175024.

It is an arithmetic number, because the mean of its divisors is an integer number (556527175024).

Almost surely, 21113054350047 is an apocalyptic number.

1113054350047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113054350047 is an equidigital number, since it uses as much as digits as its factorization.

1113054350047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25200, while the sum is 34.

Adding to 1113054350047 its reverse (7400534503111), we get a palindrome (8513588853158).

The spelling of 1113054350047 in words is "one trillion, one hundred thirteen billion, fifty-four million, three hundred fifty thousand, forty-seven".