Base | Representation |
---|---|
bin | 10000001100100111001… |
… | …101011000101011011111 |
3 | 10221101222200010110102221 |
4 | 100030213031120223133 |
5 | 121214013403200142 |
6 | 2211155145330211 |
7 | 143262344605063 |
oct | 20144715305337 |
9 | 3841880113387 |
10 | 1113054350047 |
11 | 39a053188442 |
12 | 15b873796967 |
13 | 80c644c9363 |
14 | 3bc2d13daa3 |
15 | 1de46a8b767 |
hex | 10327358adf |
1113054350047 has 2 divisors, whose sum is σ = 1113054350048. Its totient is φ = 1113054350046.
The previous prime is 1113054350041. The next prime is 1113054350099. The reversal of 1113054350047 is 7400534503111.
It is a weak prime.
It is an emirp because it is prime and its reverse (7400534503111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1113054350047 - 219 = 1113053825759 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1113054349994 and 1113054350021.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113054350041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556527175023 + 556527175024.
It is an arithmetic number, because the mean of its divisors is an integer number (556527175024).
Almost surely, 21113054350047 is an apocalyptic number.
1113054350047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113054350047 is an equidigital number, since it uses as much as digits as its factorization.
1113054350047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25200, while the sum is 34.
Adding to 1113054350047 its reverse (7400534503111), we get a palindrome (8513588853158).
The spelling of 1113054350047 in words is "one trillion, one hundred thirteen billion, fifty-four million, three hundred fifty thousand, forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •