Base | Representation |
---|---|
bin | 11001010011110010011101… |
… | …111011010101101011010010 |
3 | 112121010020012111202221011110 |
4 | 121103302131323111223102 |
5 | 104042204433114140310 |
6 | 1032423324431354150 |
7 | 32305645615032225 |
oct | 3123623573255322 |
9 | 477106174687143 |
10 | 111311022021330 |
11 | 3251581507111a |
12 | 105989a4082956 |
13 | 4a15779a336c1 |
14 | 1d6b6a728d5bc |
15 | cd06c60c6d20 |
hex | 653c9ded5ad2 |
111311022021330 has 64 divisors (see below), whose sum is σ = 273815709527808. Its totient is φ = 28942722800640.
The previous prime is 111311022021301. The next prime is 111311022021391. The reversal of 111311022021330 is 33120220113111.
It is a junction number, because it is equal to n+sod(n) for n = 111311022021297 and 111311022021306.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 23184579 + ... + 27570758.
It is an arithmetic number, because the mean of its divisors is an integer number (4278370461372).
Almost surely, 2111311022021330 is an apocalyptic number.
111311022021330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
111311022021330 is an abundant number, since it is smaller than the sum of its proper divisors (162504687506478).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111311022021330 is a wasteful number, since it uses less digits than its factorization.
111311022021330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50757171.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 111311022021330 its reverse (33120220113111), we get a palindrome (144431242134441).
The spelling of 111311022021330 in words is "one hundred eleven trillion, three hundred eleven billion, twenty-two million, twenty-one thousand, three hundred thirty".
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