Base | Representation |
---|---|
bin | 10000001100101011101… |
… | …110000001000101000111 |
3 | 10221102011221111112111111 |
4 | 100030223232001011013 |
5 | 121214142240403444 |
6 | 2211210451145451 |
7 | 143264253665554 |
oct | 20145356010507 |
9 | 3842157445444 |
10 | 1113130012999 |
11 | 39a091967104 |
12 | 15b894ba5287 |
13 | 80c7709b634 |
14 | 3bc391d7a2b |
15 | 1de4d535234 |
hex | 1032bb81147 |
1113130012999 has 2 divisors, whose sum is σ = 1113130013000. Its totient is φ = 1113130012998.
The previous prime is 1113130012993. The next prime is 1113130013101. The reversal of 1113130012999 is 9992100313111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1113130012999 - 213 = 1113130004807 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113130012993) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556565006499 + 556565006500.
It is an arithmetic number, because the mean of its divisors is an integer number (556565006500).
Almost surely, 21113130012999 is an apocalyptic number.
1113130012999 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113130012999 is an equidigital number, since it uses as much as digits as its factorization.
1113130012999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13122, while the sum is 40.
The spelling of 1113130012999 in words is "one trillion, one hundred thirteen billion, one hundred thirty million, twelve thousand, nine hundred ninety-nine".
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