Base | Representation |
---|---|
bin | 10000001100101011101… |
… | …110000001000110101101 |
3 | 10221102011221111112122021 |
4 | 100030223232001012231 |
5 | 121214142240404401 |
6 | 2211210451150141 |
7 | 143264253666061 |
oct | 20145356010655 |
9 | 3842157445567 |
10 | 1113130013101 |
11 | 39a091967197 |
12 | 15b894ba5351 |
13 | 80c7709b6b2 |
14 | 3bc391d7aa1 |
15 | 1de4d5352a1 |
hex | 1032bb811ad |
1113130013101 has 2 divisors, whose sum is σ = 1113130013102. Its totient is φ = 1113130013100.
The previous prime is 1113130012999. The next prime is 1113130013119. The reversal of 1113130013101 is 1013100313111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1110599822500 + 2530190601 = 1053850^2 + 50301^2 .
It is a cyclic number.
It is not a de Polignac number, because 1113130013101 - 231 = 1110982529453 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113130011101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556565006550 + 556565006551.
It is an arithmetic number, because the mean of its divisors is an integer number (556565006551).
Almost surely, 21113130013101 is an apocalyptic number.
It is an amenable number.
1113130013101 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113130013101 is an equidigital number, since it uses as much as digits as its factorization.
1113130013101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27, while the sum is 16.
Adding to 1113130013101 its reverse (1013100313111), we get a palindrome (2126230326212).
The spelling of 1113130013101 in words is "one trillion, one hundred thirteen billion, one hundred thirty million, thirteen thousand, one hundred one".
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