Base | Representation |
---|---|
bin | 10100101110111101… |
… | …00010100110010111 |
3 | 1001201202111122022112 |
4 | 22113132202212113 |
5 | 140244103101442 |
6 | 5040314221235 |
7 | 542562330254 |
oct | 122736424627 |
9 | 31652448275 |
10 | 11131300247 |
11 | 47a23686a1 |
12 | 21a7a2481b |
13 | 10851a9bc2 |
14 | 7784cc42b |
15 | 452378082 |
hex | 2977a2997 |
11131300247 has 2 divisors, whose sum is σ = 11131300248. Its totient is φ = 11131300246.
The previous prime is 11131300223. The next prime is 11131300259. The reversal of 11131300247 is 74200313111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11131300247 - 216 = 11131234711 is a prime.
It is a super-2 number, since 2×111313002472 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11131300277) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5565650123 + 5565650124.
It is an arithmetic number, because the mean of its divisors is an integer number (5565650124).
Almost surely, 211131300247 is an apocalyptic number.
11131300247 is a deficient number, since it is larger than the sum of its proper divisors (1).
11131300247 is an equidigital number, since it uses as much as digits as its factorization.
11131300247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 11131300247 its reverse (74200313111), we get a palindrome (85331613358).
The spelling of 11131300247 in words is "eleven billion, one hundred thirty-one million, three hundred thousand, two hundred forty-seven".
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