Base | Representation |
---|---|
bin | 110011110101011000… |
… | …1110110111101111011 |
3 | 101122022121021102221122 |
4 | 1213222301312331323 |
5 | 3310432124334042 |
6 | 123045254255455 |
7 | 11020304626664 |
oct | 1475261667573 |
9 | 348277242848 |
10 | 111313121147 |
11 | 4323139a4a8 |
12 | 196a665758b |
13 | a65c57a277 |
14 | 555d75c36b |
15 | 2d6752a7d2 |
hex | 19eac76f7b |
111313121147 has 2 divisors, whose sum is σ = 111313121148. Its totient is φ = 111313121146.
The previous prime is 111313120993. The next prime is 111313121149. The reversal of 111313121147 is 741121313111.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 111313121147 - 234 = 94133251963 is a prime.
It is a super-2 number, since 2×1113131211472 (a number of 23 digits) contains 22 as substring.
Together with 111313121149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (111313121149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55656560573 + 55656560574.
It is an arithmetic number, because the mean of its divisors is an integer number (55656560574).
Almost surely, 2111313121147 is an apocalyptic number.
111313121147 is a deficient number, since it is larger than the sum of its proper divisors (1).
111313121147 is an equidigital number, since it uses as much as digits as its factorization.
111313121147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 504, while the sum is 26.
Adding to 111313121147 its reverse (741121313111), we get a palindrome (852434434258).
The spelling of 111313121147 in words is "one hundred eleven billion, three hundred thirteen million, one hundred twenty-one thousand, one hundred forty-seven".
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