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11131313030300 = 22521071973527273
BaseRepresentation
bin1010000111111011010111…
…1101011000010010011100
31110102010212100021202220002
42201332311331120102130
52424333412113432200
635401353221313432
72226132212421341
oct241766575302234
943363770252802
1011131313030300
113601844016151
1212b93a6265878
136298a8346798
142a6a891947c8
1514483e933bd5
hexa1fb5f5849c

11131313030300 has 72 divisors (see below), whose sum is σ = 24393099897936. Its totient is φ = 4408668828160.

The previous prime is 11131313030287. The next prime is 11131313030303. The reversal of 11131313030300 is 303031313111.

It is a super-2 number, since 2×111313130303002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11131313030303) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 20847464 + ... + 21374736.

It is an arithmetic number, because the mean of its divisors is an integer number (338793054138).

Almost surely, 211131313030300 is an apocalyptic number.

11131313030300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11131313030300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (12196549948968).

11131313030300 is an abundant number, since it is smaller than the sum of its proper divisors (13261786867636).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11131313030300 is a wasteful number, since it uses less digits than its factorization.

11131313030300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 529367 (or 529360 counting only the distinct ones).

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 11131313030300 its reverse (303031313111), we get a palindrome (11434344343411).

The spelling of 11131313030300 in words is "eleven trillion, one hundred thirty-one billion, three hundred thirteen million, thirty thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 107 214 428 535 1070 1973 2140 2675 3946 5350 7892 9865 10700 19730 39460 49325 98650 197300 211111 422222 527273 844444 1054546 1055555 2109092 2111110 2636365 4222220 5272730 5277775 10545460 10555550 13181825 21111100 26363650 52727300 56418211 112836422 225672844 282091055 564182110 1040309629 1128364220 1410455275 2080619258 2820910550 4161238516 5201548145 5641821100 10403096290 20806192580 26007740725 52015481450 104030962900 111313130303 222626260606 445252521212 556565651515 1113131303030 2226262606060 2782828257575 5565656515150 11131313030300