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11132013643 is a prime number
BaseRepresentation
bin10100101111000010…
…10000110001001011
31001201210211212220121
422113201100301023
5140244243414033
65040341404111
7542601361162
oct122741206113
931653755817
1011132013643
1147a2805683
1221a8109637
13108539982a
147786363d9
1545246962d
hex297850c4b

11132013643 has 2 divisors, whose sum is σ = 11132013644. Its totient is φ = 11132013642.

The previous prime is 11132013637. The next prime is 11132013679. The reversal of 11132013643 is 34631023111.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11132013643 - 229 = 10595142731 is a prime.

It is not a weakly prime, because it can be changed into another prime (11132013143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566006821 + 5566006822.

It is an arithmetic number, because the mean of its divisors is an integer number (5566006822).

Almost surely, 211132013643 is an apocalyptic number.

11132013643 is a deficient number, since it is larger than the sum of its proper divisors (1).

11132013643 is an equidigital number, since it uses as much as digits as its factorization.

11132013643 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 11132013643 its reverse (34631023111), we get a palindrome (45763036754).

The spelling of 11132013643 in words is "eleven billion, one hundred thirty-two million, thirteen thousand, six hundred forty-three".