Base | Representation |
---|---|
bin | 10100101111000010… |
… | …10000110001001011 |
3 | 1001201210211212220121 |
4 | 22113201100301023 |
5 | 140244243414033 |
6 | 5040341404111 |
7 | 542601361162 |
oct | 122741206113 |
9 | 31653755817 |
10 | 11132013643 |
11 | 47a2805683 |
12 | 21a8109637 |
13 | 108539982a |
14 | 7786363d9 |
15 | 45246962d |
hex | 297850c4b |
11132013643 has 2 divisors, whose sum is σ = 11132013644. Its totient is φ = 11132013642.
The previous prime is 11132013637. The next prime is 11132013679. The reversal of 11132013643 is 34631023111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11132013643 - 229 = 10595142731 is a prime.
It is not a weakly prime, because it can be changed into another prime (11132013143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566006821 + 5566006822.
It is an arithmetic number, because the mean of its divisors is an integer number (5566006822).
Almost surely, 211132013643 is an apocalyptic number.
11132013643 is a deficient number, since it is larger than the sum of its proper divisors (1).
11132013643 is an equidigital number, since it uses as much as digits as its factorization.
11132013643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 11132013643 its reverse (34631023111), we get a palindrome (45763036754).
The spelling of 11132013643 in words is "eleven billion, one hundred thirty-two million, thirteen thousand, six hundred forty-three".
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