Base | Representation |
---|---|
bin | 10100101111000010… |
… | …10000101001010111 |
3 | 1001201210211212020002 |
4 | 22113201100221113 |
5 | 140244243410033 |
6 | 5040341401515 |
7 | 542601356546 |
oct | 122741205127 |
9 | 31653755202 |
10 | 11132013143 |
11 | 47a2805269 |
12 | 21a810929b |
13 | 1085399534 |
14 | 77863615d |
15 | 4524693e8 |
hex | 297850a57 |
11132013143 has 2 divisors, whose sum is σ = 11132013144. Its totient is φ = 11132013142.
The previous prime is 11132013089. The next prime is 11132013199. The reversal of 11132013143 is 34131023111.
It is a weak prime.
It is an emirp because it is prime and its reverse (34131023111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11132013143 - 218 = 11131750999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11132013643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566006571 + 5566006572.
It is an arithmetic number, because the mean of its divisors is an integer number (5566006572).
Almost surely, 211132013143 is an apocalyptic number.
11132013143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11132013143 is an equidigital number, since it uses as much as digits as its factorization.
11132013143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 11132013143 its reverse (34131023111), we get a palindrome (45263036254).
The spelling of 11132013143 in words is "eleven billion, one hundred thirty-two million, thirteen thousand, one hundred forty-three".
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