Base | Representation |
---|---|
bin | 110011110101100110… |
… | …0111001111100001110 |
3 | 101122100002121122200201 |
4 | 1213223030321330032 |
5 | 3310440433224324 |
6 | 123050110244114 |
7 | 11020422116512 |
oct | 1475314717416 |
9 | 348302548621 |
10 | 111320211214 |
11 | 432353a2363 |
12 | 196a8ab663a |
13 | a660b90484 |
14 | 5560686142 |
15 | 2d67e7b444 |
hex | 19eb339f0e |
111320211214 has 4 divisors (see below), whose sum is σ = 166980316824. Its totient is φ = 55660105606.
The previous prime is 111320211199. The next prime is 111320211341. The reversal of 111320211214 is 412112023111.
111320211214 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 412112023111 = 199 ⋅2070914689.
It is a junction number, because it is equal to n+sod(n) for n = 111320211191 and 111320211200.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27830052802 + ... + 27830052805.
It is an arithmetic number, because the mean of its divisors is an integer number (41745079206).
Almost surely, 2111320211214 is an apocalyptic number.
111320211214 is a deficient number, since it is larger than the sum of its proper divisors (55660105610).
111320211214 is an equidigital number, since it uses as much as digits as its factorization.
111320211214 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55660105609.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 111320211214 its reverse (412112023111), we get a palindrome (523432234325).
The spelling of 111320211214 in words is "one hundred eleven billion, three hundred twenty million, two hundred eleven thousand, two hundred fourteen".
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