1113212414021 has 2 divisors, whose sum is σ = 1113212414022. Its totient is φ = 1113212414020.

The previous prime is 1113212414011. The next prime is 1113212414023. The reversal of 1113212414021 is 1204142123111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 837387877921 + 275824536100 = 915089^2 + 525190^2 .

It is an emirp because it is prime and its reverse (1204142123111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1113212414021 - 2¹⁴ = 1113212397637 is a prime.

Together with 1113212414023, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1113212414023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556606207010 + 556606207011.

It is an arithmetic number, because the mean of its divisors is an integer number (556606207011).

Almost surely, 2^{1113212414021} is an apocalyptic number.

It is an amenable number.

1113212414021 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113212414021 is an equidigital number, since it uses as much as digits as its factorization.

1113212414021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 1113212414021 its reverse (1204142123111), we get a palindrome (2317354537132).

The spelling of 1113212414021 in words is "one trillion, one hundred thirteen billion, two hundred twelve million, four hundred fourteen thousand, twenty-one".