Base | Representation |
---|---|
bin | 10000001100110000101… |
… | …011011000111010001101 |
3 | 10221102101202001101200021 |
4 | 100030300223120322031 |
5 | 121214330040212003 |
6 | 2211223022302141 |
7 | 143266314106264 |
oct | 20146053307215 |
9 | 3842352041607 |
10 | 1113213210253 |
11 | 39a124921471 |
12 | 15b8b8a27951 |
13 | 80c8b3ab091 |
14 | 3bc462935db |
15 | 1de559bb2bd |
hex | 10330ad8e8d |
1113213210253 has 2 divisors, whose sum is σ = 1113213210254. Its totient is φ = 1113213210252.
The previous prime is 1113213210227. The next prime is 1113213210313. The reversal of 1113213210253 is 3520123123111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1004799745609 + 108413464644 = 1002397^2 + 329262^2 .
It is a cyclic number.
It is not a de Polignac number, because 1113213210253 - 233 = 1104623275661 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113213210653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556606605126 + 556606605127.
It is an arithmetic number, because the mean of its divisors is an integer number (556606605127).
Almost surely, 21113213210253 is an apocalyptic number.
It is an amenable number.
1113213210253 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113213210253 is an equidigital number, since it uses as much as digits as its factorization.
1113213210253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 1113213210253 its reverse (3520123123111), we get a palindrome (4633336333364).
The spelling of 1113213210253 in words is "one trillion, one hundred thirteen billion, two hundred thirteen million, two hundred ten thousand, two hundred fifty-three".
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