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11133021311 is a prime number
BaseRepresentation
bin10100101111001010…
…00110110001111111
31001201212202002011122
422113211012301333
5140300023140221
65040415141155
7542613056036
oct122745066177
931655662148
1011133021311
1147a3333765
1221a85147bb
131085660399
1477881971d
154525b7eab
hex297946c7f

11133021311 has 2 divisors, whose sum is σ = 11133021312. Its totient is φ = 11133021310.

The previous prime is 11133021283. The next prime is 11133021313. The reversal of 11133021311 is 11312033111.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11133021311 - 210 = 11133020287 is a prime.

It is a super-2 number, since 2×111330213112 (a number of 21 digits) contains 22 as substring.

Together with 11133021313, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11133021311.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11133021313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566510655 + 5566510656.

It is an arithmetic number, because the mean of its divisors is an integer number (5566510656).

Almost surely, 211133021311 is an apocalyptic number.

11133021311 is a deficient number, since it is larger than the sum of its proper divisors (1).

11133021311 is an equidigital number, since it uses as much as digits as its factorization.

11133021311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11133021311 its reverse (11312033111), we get a palindrome (22445054422).

The spelling of 11133021311 in words is "eleven billion, one hundred thirty-three million, twenty-one thousand, three hundred eleven".