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111331542013 is a prime number
BaseRepresentation
bin110011110101111100…
…0001000001111111101
3101122100212221022121221
41213223320020033331
53311001333321023
6123051153153341
711020620331066
oct1475370101775
9348325838557
10111331542013
114324083135a
12196b085b851
13a6633299a3
145561d9556d
152d68e6885d
hex19ebe083fd

111331542013 has 2 divisors, whose sum is σ = 111331542014. Its totient is φ = 111331542012.

The previous prime is 111331541999. The next prime is 111331542019. The reversal of 111331542013 is 310245133111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82729291129 + 28602250884 = 287627^2 + 169122^2 .

It is an emirp because it is prime and its reverse (310245133111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111331542013 - 221 = 111329444861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111331542019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55665771006 + 55665771007.

It is an arithmetic number, because the mean of its divisors is an integer number (55665771007).

Almost surely, 2111331542013 is an apocalyptic number.

It is an amenable number.

111331542013 is a deficient number, since it is larger than the sum of its proper divisors (1).

111331542013 is an equidigital number, since it uses as much as digits as its factorization.

111331542013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 111331542013 its reverse (310245133111), we get a palindrome (421576675124).

The spelling of 111331542013 in words is "one hundred eleven billion, three hundred thirty-one million, five hundred forty-two thousand, thirteen".