Base | Representation |
---|---|
bin | 10000001100110111101… |
… | …010000110011110101010 |
3 | 10221102200220101211121212 |
4 | 100030313222012132222 |
5 | 121220100030010010 |
6 | 2211242404233122 |
7 | 143302235343140 |
oct | 20146752063652 |
9 | 3842626354555 |
10 | 1113330313130 |
11 | 39a184a34602 |
12 | 15b93009b7a2 |
13 | 80ca972c419 |
14 | 3bc57a57590 |
15 | 1de60ded505 |
hex | 10337a867aa |
1113330313130 has 128 divisors (see below), whose sum is σ = 2435590080000. Its totient is φ = 357914972160.
The previous prime is 1113330313099. The next prime is 1113330313177. The reversal of 1113330313130 is 313130333111.
It is a super-2 number, since 2×11133303131302 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1113330313096 and 1113330313105.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 152069870 + ... + 152077190.
It is an arithmetic number, because the mean of its divisors is an integer number (19028047500).
Almost surely, 21113330313130 is an apocalyptic number.
1113330313130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1113330313130 is an abundant number, since it is smaller than the sum of its proper divisors (1322259766870).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1113330313130 is a wasteful number, since it uses less digits than its factorization.
1113330313130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8512.
The product of its (nonzero) digits is 729, while the sum is 23.
Adding to 1113330313130 its reverse (313130333111), we get a palindrome (1426460646241).
The spelling of 1113330313130 in words is "one trillion, one hundred thirteen billion, three hundred thirty million, three hundred thirteen thousand, one hundred thirty".
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